What is the balanced chemical equation for: Liquid methanol (CH3OH) combusted in oxygen gas to yield carbon dioxide gas and liquid water?

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What is the balanced chemical equation for: Liquid methanol (CH3OH) combusted in oxygen gas to yield carbon dioxide gas and liquid water?

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Answer 1 · 2014-08-22T04:01:15

The balanced chemical equation for the combustion of liquid methanol in oxygen gas to yield carbon dioxide gas and liquid water is:

$2 {CH}_{3} O H (l)$ $"2""CH"_3"O""H""(l)"$ + $3 O_{2} (g)$ $"3""O"_2"(g)"$ $\to$ $rarr$ $2 {CO}_{2} (g)$ $"2""CO"_2"(g)"$ + $4 H_{2} O (l)$ $"4""H"_2"O""(l)"$

If you multiply the coefficients (the numbers in front) times the subscripts for each element in each formula, you will find that there are 2 atoms of carbon, 8 atoms of hydrogen, and 8 atoms of oxygen on both sides of the equation, so it is balanced.

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What is the balanced chemical equation for: Liquid methanol (CH3OH) combusted in oxygen gas to yield carbon dioxide gas and liquid water?

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