What is the balanced equation for the complete combustion of $C_{3} H_{7} C O C_{2} H_{5}$ $C_3H_7COC_2H_5$ ?

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What is the balanced equation for the complete combustion of $C_{3} H_{7} C O C_{2} H_{5}$ $C_3H_7COC_2H_5$ ?

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Answer 1 · 2016-01-21T17:24:20

$2 C_{3} H_{7} C O C_{2} H_{5} + 17 O_{2} \to 12 C O_{2} + 12 H_{2} O$ $2C_3H_7COC_2H_5+17O_2->12CO_2+12H_2O$

Explanation:

Complete combustion of $C_{3} H_{7} C O C_{2} H_{5}$ $C_3H_7COC_2H_5$ in oxygen will produce Carbon dioxide and water. If $a, b, c, d$ $a,b,c,d$ are the respective molecules in the balanced equation, we have

$a C_{3} H_{7} C O C_{2} H_{5} + b O_{2} \to c C O_{2} + d H_{2} O$ $aC_3H_7COC_2H_5+bO_2->cCO_2+dH_2O$

Lets start with $a = 1$ $a=1$ . Balancing the number of carbon on both sides we obtain $c = 6$ $c=6$ . And the equation becomes
$a C_{3} H_{7} C O C_{2} H_{5} + b O_{2} \to 6 C O_{2} + 6 H_{2} O$ $aC_3H_7COC_2H_5+bO_2->6CO_2+6H_2O$

$C_{3} H_{7} C O C_{2} H_{5} + b O_{2} \to 6 C O_{2} + d H_{2} O$ $C_3H_7COC_2H_5+bO_2->6CO_2+dH_2O$
Now balancing hydrogen atoms we obtain $d = 6$ $d=6$ . And the equation becomes

$C_{3} H_{7} C O C_{2} H_{5} + b O_{2} \to 6 C O_{2} + 6 H_{2} O$ $C_3H_7COC_2H_5+bO_2->6CO_2+6H_2O$
Now balancing $O$ $O$ atoms we see that it $b = \frac{17}{2}$ $b=17/2$
Multiplying all with 2 we obtain balanced equation as

$2 C_{3} H_{7} C O C_{2} H_{5} + 17 O_{2} \to 12 C O_{2} + 12 H_{2} O$ $2C_3H_7COC_2H_5+17O_2->12CO_2+12H_2O$

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What is the balanced equation for the complete combustion of $C_{3} H_{7} C O C_{2} H_{5}$ $C_3H_7COC_2H_5$ ?

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What is the balanced equation for the complete combustion of C3H7COC2H5C_3H_7COC_2H_5?

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What is the balanced equation for the complete combustion of $C_{3} H_{7} C O C_{2} H_{5}$ $C_3H_7COC_2H_5$ ?