What is the center of the sphere with the equation (x-2)^2+(y+3)^2+(z-6)^2=36?

2 Answers
Sep 1, 2015

(2,-3,6)

Explanation:

The center of any sphere written in the form:
(x-a)+(y-b)+(z-c)=r^2" ", is (a,b,c)

(x-2)^2+(y+3)^2+(z-6)^2=36 can be written as:

(x-2)^2+(y-(-3))^2+(z-6)^2=(6)^2

hence center is at color(blue)((2","-3","6))

Sep 1, 2015

The centre has coordinates: (+2,-3,+6)

Explanation:

If an equation of a circle (a sphere) is given in such form, then:

1) The coordinates of the centre are values next to x,y (and z) with changed signs,

2) Radius is the square root of the value on right hand side