What is the centroid of a triangle with corners at $(5, 1)$ $(5, 1)$ , $(4, 9)$ $(4, 9)$ , and $(7, 2)$ $(7,2)$ ?

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What is the centroid of a triangle with corners at $(5, 1)$ $(5, 1)$ , $(4, 9)$ $(4, 9)$ , and $(7, 2)$ $(7,2)$ ?

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Answer 1 · 2016-01-15T23:56:12

$(\frac{16}{3}, 4)$ $(16/3,4)$

Explanation:

Given the 3 vertices of a 2-dimensional triangle its centroid is found in this way
$(\frac{x_{1} + x_{2} + x_{2}}{3}, \frac{y_{1} + y_{2} + y_{3}}{3})$ $((x_1+x_2+x_2)/3,(y_1+y_2+y_3)/3)$

In case,
$(\frac{5 + 4 + 7}{3}, \frac{1 + 9 + 2}{3})$ $((5+4+7)/3,(1+9+2)/3)$
$(\frac{16}{3}, \frac{12}{3}) = (\frac{16}{3}, 4)$ $(16/3,12/3)=(16/3,4)$

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What is the centroid of a triangle with corners at $(5, 1)$ $(5, 1)$ , $(4, 9)$ $(4, 9)$ , and $(7, 2)$ $(7,2)$ ?

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Explanation:

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