What is the change in volume when 4.8 L sample of N_2(g) is heated from 388.0°C to 700°C?

1 Answer
Feb 27, 2017

We use "Charles's Law", VpropT, we get V_2~=7L

Explanation:

If VpropT, then V=kT, and given the conditions (constant pressure, and constant amount of gas), we can solve for k:

V_1/T_1=V_2/T_2, where T="temperatura assoluta"

We solve for V_2=V_1/T_1xxT_2

=(4.8*L)/(661*cancelK)xx973*cancelK =??L