What is the change in volume when 4.8 L sample of N_2(g)N2(g) is heated from 388.0°C to 700°C?

1 Answer
Feb 27, 2017

We use "Charles's Law"Charles's Law, VpropTVT, we get V_2~=7LV27L

Explanation:

If VpropTVT, then V=kTV=kT, and given the conditions (constant pressure, and constant amount of gas), we can solve for kk:

V_1/T_1=V_2/T_2V1T1=V2T2, where T="temperatura assoluta"T=temperatura assoluta

We solve for V_2=V_1/T_1xxT_2V2=V1T1×T2

=(4.8*L)/(661*cancelK)xx973*cancelK =??L