What is the coefficient of oxygen gas after balancing the following equation, $P (s) + O_{2} \to P_{2} O_{5} (s)$ $P(s) + O_2 -> P_2O_5(s)$ ?

Question

6617 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-08-07T06:33:32

$\frac{5}{2} ?$ $5/2?$ Of course the $P$ $P$ coefficient has to be changed as well.

Of course, if you like, you can make a meal of the the equation:

$P_{4} (s) + 5 O_{2} (g) \to P_{4} O_{10} (s)$ $P_4(s) + 5O_2(g) rarr P_4O_10(s)$

The stoichiometry, the grams of reactant required for the grams of product, is precisely the same in each equation.

What is the coefficient of oxygen gas after balancing the following equation, P(s)+O2→P2O5(s)P(s) + O_2 -> P_2O_5(s)?