What is the cross product of <2,5,−3> and <5,6,−2>?

1 Answer
ali ergin
Feb 13, 2016

AXB=<8,−11−13>

Explanation:

(a,b,c)X(d,e,f)=(b⋅f−e⋅c)−(a⋅f−c⋅d)+(a⋅e−b⋅d)
A=(2,5,−3) ;B=(5,6,−2)
AXB=(5⋅(−2)−(−3⋅6))−(2⋅(−2)−(−3⋅5))+(2⋅6−5⋅5)
AXB=(−10+18)−(−4+15)+(12−25)
AXB=8i−11j−13k
AXB=<8,−11−13>

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