What is the density of hydrogen gas using the ideal gas law?

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Answer 1 · 2018-06-02T15:24:46

Of course, for $"density"$ we need to SPECIFY.... $"temperature"$ and $"pressure...."$

And, using standard conditions of $P=1*atm$ ...and $T=298*K$ , we address the Ideal Gas equation...(at least near standard conditions....)

$PV=nRT$ ... $n/V=P/(RT)=("mass"/"molar mass")/V=P/(RT)$

And so....

$underbrace("mass"/V)_("density"=rho)=P/(RT)xx"molar mass"$

And thus our working equation... $rho_(H_2)=P/(RT)xx2.016*g*mol^-1$

$=(1*atmxx2.016*g*mol^-1)/(0.0821*(L*atm)/(K*mol)xx298*K)~=0.1*g*L^-1$

We note that hydrogen gas, as are all elemental gases with any chemistry, is bimolecular, i.e. $H_2$ ...