What is the derivative of # (4-x^2)^4#? Calculus Basic Differentiation Rules Chain Rule 1 Answer ali ergin Jul 9, 2016 #(d y)/(d x)=-8x(4-x^2)^3# Explanation: #y=(4-x^2)^4" ; "(d y)/(d x)=?# #(d y)/(d x)=4(4-x^2)^3*(-2x)=-8x(4-x^2)^3# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 1079 views around the world You can reuse this answer Creative Commons License