What is the derivative of #5^(3x)#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Jim H Mar 2, 2018 Please see below. Explanation: #d/dx(a^x) = a^x lna# So, #d/dx(a^u) = (a^u lna) (du)/dx# So #d/dx(5^(3x)) = (5^(3x) ln5) (3)# # = 3(5^(3x))ln5# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 13353 views around the world You can reuse this answer Creative Commons License