What is the derivative of #cos^7(e^x)#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Sonnhard Jun 6, 2018 #y'=7cos^6(e^x)(-sin(e^(x)))*e^x# Explanation: By the power and the chain rule we get #y'=7cos^(7-1)*(-sin(e^x))*e^x# since #(cos(x))'=-sin(x)# #(e^x)'=e^x# Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 2074 views around the world You can reuse this answer Creative Commons License