Question

What is the derivative of `f(x)=x^3-3x`?

Answer 1

`f'(x) = 3(x^2-1)`

Explanation:

The power rule for derivatives tells us that

`d/(dx)[x^n] = n*x^(n-1)`

By applying this rule to this problem, we can see that

`f'(x) = 3x^2 - 3 = 3(x^2-1)`