What is the derivative of $f(x) = x^3 - 3x^2 - 1$ ?

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Answer 1 · 2018-07-08T18:13:16

$f'(x)=3x^2-6x$

We need the sum rule
$(u+v+w)'=u'+v'+w'$
and that

$(x^n)'=nx^(n-1)$

so we get

$f'(x)=3x^2-6x$

Answer 2 · 2018-07-08T21:55:15

$f'(x)=3x^2-6x$

$"differentiate each term using the "color(blue)"power rule"$

$•color(white)(x)d/dx(ax^n)=nax^(n-1)$

$f'(x)=3x^2-6x$

Answer 3 · 2018-07-08T23:11:36

$3x^2-6x$

The derivative of a sum/difference is the same as the sum/difference of the derivatives, so we can take the derivative of all of these terms.

We can use the Power Rule- here, the exponent is brought out front, and the power is decremented by $1$ . We get

$3x^2-6x$

Recall that the derivative of a constant is zero.

Hope this helps!

What is the derivative of f(x) = x^3 - 3x^2 - 1f(x) = x^3 - 3x^2 - 1?