What is the derivative of #ln(2x+1)#? Calculus Basic Differentiation Rules Chain Rule 1 Answer Andrea S. Jul 29, 2018 #d/dx (ln (2x+1)) = 2/(2x+1) # Explanation: Using the chain rule: #d/dx (ln (2x+1)) = 1/(2x+1) d/dx (2x+1)# #d/dx (ln (2x+1)) = 2/(2x+1) # Answer link Related questions What is the Chain Rule for derivatives? How do you find the derivative of #y= 6cos(x^2)# ? How do you find the derivative of #y=6 cos(x^3+3)# ? How do you find the derivative of #y=e^(x^2)# ? How do you find the derivative of #y=ln(sin(x))# ? How do you find the derivative of #y=ln(e^x+3)# ? How do you find the derivative of #y=tan(5x)# ? How do you find the derivative of #y= (4x-x^2)^10# ? How do you find the derivative of #y= (x^2+3x+5)^(1/4)# ? How do you find the derivative of #y= ((1+x)/(1-x))^3# ? See all questions in Chain Rule Impact of this question 19363 views around the world You can reuse this answer Creative Commons License