Question

What is the derivative of `lnx^2`?

Answer 1

`f(x)=lnx^2 = 2 lnx`

`f'(x) = 2 1/x = 2/x`

That is the easy way. If 9you prefer, use `d/(dx)(lnu) = 1/u (du)/dx`
to get:

`f'(x) = 1/x^2 * 2x = (2x)/x^2 = 2/x`