What is the derivative of #(lnx)^2#? Calculus Differentiating Logarithmic Functions Differentiating Logarithmic Functions with Base e 1 Answer GiĆ³ Apr 7, 2015 I would use the Chain Rule, deriving the #()^2# first and then the #ln# getting: #2*(ln(x))*1/x=2/xln(x)# Answer link Related questions What is the derivative of #f(x)=ln(g(x))# ? What is the derivative of #f(x)=ln(x^2+x)# ? What is the derivative of #f(x)=ln(e^x+3)# ? What is the derivative of #f(x)=x*ln(x)# ? What is the derivative of #f(x)=e^(4x)*ln(1-x)# ? What is the derivative of #f(x)=ln(x)/x# ? What is the derivative of #f(x)=ln(cos(x))# ? What is the derivative of #f(x)=ln(tan(x))# ? What is the derivative of #f(x)=sqrt(1+ln(x)# ? What is the derivative of #f(x)=(ln(x))^2# ? See all questions in Differentiating Logarithmic Functions with Base e Impact of this question 1695 views around the world You can reuse this answer Creative Commons License