What is the derivative of mx+bmx+b?

1 Answer
Dec 21, 2014

Considering the function (linear): y=mx+by=mx+b where m and b are real numbers, the derivative, y', of this function (with respect to x) is:
y'=m

This function, y=mx+b, represents, graphically, a straight line and the number m represents the SLOPE of the line (or if you want the inclination of the line).
As you can see deriving the linear function y=mx+b gives you m, the slope of the line which is a quite rearcable result, widely used in Calculus!

As an example you can consider the function:
y=4x+5
you can derive each factor:
derivative of 4x is 4
derivative of 5 is 0
and then add them together to get:
y'=4+0=4

(Remember that the derivative of a constant, k, is zero, the derivative of k*x^n is knx^(n-1) and that x^0=1 )