What is the derivative of ${sin}^{2} (6 x)$ $sin^2 (6x)$ ?

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Answer 1 · 2015-04-07T00:58:37

I would use the Chain Rule deriving ${()}^{2}$ $()^2$ first then the $sin$ $sin$ and finally the argument $6 x$ $6x$ :

$2 \cdot sin (6 x) \cdot cos (6 x) \cdot 6 = 12 sin (6 x) cos (6 x)$ $2*sin(6x)*cos(6x)*6=12sin(6x)cos(6x)$

What is the derivative of sin^2 (6x)sin2(6x)sin^2 (6x)?