What is the derivative of $(-sinx^2)/2$ ?

Question

2018 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-05-29T23:19:10

$d/dx( -sinx^2/2) = -x cosx^2$

Using the chain rule with $u= x^2$ :

$d/dx( -sinx^2/2) = -1/2 d/(du) (sinu) xx (du)/dx$

$d/dx( -sinx^2/2) = -1/2 cosx^2 xx (dx^2)/dx$

$d/dx( -sinx^2/2) = -1/2 cosx^2 xx 2x$

$d/dx( -sinx^2/2) = -x cosx^2$

What is the derivative of (-sinx^2)/2(-sinx^2)/2?