Question

What is the derivative of `sqrt(8x+1)`?

Answer 1

`d/dxsqrt(8x+1) =4/sqrt(8x+1)`

Explanation:

Applying the chain rule:

`d/dxsqrt(8x+1) = d/dx(8x+1)^(1/2)`

`= 1/2(8x+1)^(-1/2)*(d/dx(8x+1))`

`=1/(2sqrt(8x+1))*8`

`=4/sqrt(8x+1)`