What is the derivative of this function (cos x) / (1-sinx)? Calculus Differentiating Trigonometric Functions Intuitive Approach to the derivative of y=sin(x) 1 Answer Ratnaker Mehta Oct 22, 2017 secx(secx+tanx). Explanation: Let, y=cosx/(1-sinx). :. y=cosx/(1-sinx)xx(1+sinx)/(1+sinx), =(cosx(1+sinx))/(1-sin^2x)=(cosx(1+sinx))/cos^2x. :. y=(1+sinx)/cosx=1/cosx+sinx/cosx, i.e., y=secx+tanx. rArr dy/dx=secxtanx+sec^2x=secx(tanx+secx). Answer link Related questions What is the derivative of -sin(x)? What is the derivative of sin(2x)? How do I find the derivative of y=sin(2x) - 2sin(x)? How do you find the second derivative of y=2sin3x-5sin6x? How do you compute d/dx 3sinh(3/x)? How do you find the derivative y=xsinx + cosx? What is the derivative of sin(x^2y^2)? What is f'(-pi/3) when you are given f(x)=sin^7(x)? How do you find the fist and second derivative of pi*sin(pix)? If f(x)= 2x sin(x) cos(x), how do you find f'(x)? See all questions in Intuitive Approach to the derivative of y=sin(x) Impact of this question 1817 views around the world You can reuse this answer Creative Commons License