Question

What is the derivative of this function `sin(x+1)`?

Answer 1

`f(x)' = cos(x+1)`

Explanation:

Use the chain rule: `(sin u)' = (cos u)u'`

Let `u = x + 1`, so `u' = 1`

`f(x)' = (cos(x+1))(1) = cos(x+1)`