Question

What is the derivative of this function `sin(x^3+1)`?

Answer 1

`d/dxsin(x^3+1) = 3xcos(x^3+1)`

Explanation:

Use the chain rule:

`d/dxsin(x^3+1) = cos(x^3+1).(3x)`
`:. d/dxsin(x^3+1) = 3xcos(x^3+1)`