Question

What is the derivative of `(x + 1)/y`?

Answer 1

`d/dx((x+1)/y) = ( y-(x+1) dy/dx)/y^2`

Explanation:

Use the quotient rule and the chain rule. (all implicit differentiation uses the chain rule.)

`d/dx((x+1)/y) = ((1)y-(x+1) dy/dx)/y^2`

There's not much more we can do without the rest of the equation relating `x` and `y`.

We could rewrite a bit, to get:

`= ( y-(x+1) dy/dx)/y^2`

or

`= 1/y - (x+1)/y^2 dy/dx`