What is the derivative of $x^{2}$ $x^2$ ?

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Answer 1 · 2018-05-23T15:11:29

$2 x$ $2x$

Use that $(x^n)'=nx^(n-1)$

Answer 2 · 2018-05-23T19:10:00

$2x$

Anytime we see a polynomial, we can use the Power Rule (see below) to find its derivative.

With the Power Rule, the exponent comes out front of the variable, and the power gets decremented by $1$ . Doing this, we get

$2x^1$ , or

$2x$

Hope this helps!

Answer 3 · 2018-05-23T20:09:40

$2x$

By first principles:

$lim_( h to 0) (f(x+h) - f(x) )/ h = (dy)/(dx)$

$=> lim_(h to 0)( (x+h)^2 - x^2 )/ h$

$=> lim_(h to 0) ( x^2 +2xh + h^2 - x^2)/ h$

$=> lim_(h to 0) ( 2xh + h^2 )/ h$

$=> lim_(h to 0) 2x + h$

$= 2x$

What is the derivative of x^2x2x^2?