What is the derivative of $x^2/3 - 3/x^2$ ?

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Answer 1 · 2018-01-22T03:13:57

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Answer 2 · 2018-01-22T03:21:02

$f'(x)=(2x)/3+6/(x^3)$

Given: $f(x)=x^2/3-3/x^2$

$f'(x)=1/3d/dx[x^2]-3d/dx[1/x^2]$

$d/dx[x^2]=2x$

$d/dx[1/x^2]=>d/dx[x^-2]=-2x^(-2-1)=-2x^(-3)=-2/(x^3)$

$f'(x)=1/3*2x-3*-2/(x^3)=(2x)/3+6/(x^3)$

What is the derivative of x^2/3 - 3/x^2 x^2/3 - 3/x^2?