What is the derivative of #x*x^(1/2)#? Calculus Basic Differentiation Rules Product Rule 1 Answer Noah G Dec 23, 2016 The derivative is #3/2sqrt(x)#. Explanation: #x * x^(1/2) = x^(1+ 1/2) = x^(2/2 + 1/2) = x^(3/2)#. The power rule states that #d/dx(x^n) = nx^(n - 1)# #d/dx(x^(3/2)) = 3/2x^(1/2) = 3/2sqrt(x)# Answer link Related questions What is the Product Rule for derivatives? How do you apply the product rule repeatedly to find the derivative of #f(x) = (x - 3)(2 - 3x)(5 - x)# ? How do you use the product rule to find the derivative of #y=x^2*sin(x)# ? How do you use the product rule to differentiate #y=cos(x)*sin(x)# ? How do you apply the product rule repeatedly to find the derivative of #f(x) = (x^4 +x)*e^x*tan(x)# ? How do you use the product rule to find the derivative of #y=(x^3+2x)*e^x# ? How do you use the product rule to find the derivative of #y=sqrt(x)*cos(x)# ? How do you use the product rule to find the derivative of #y=(1/x^2-3/x^4)*(x+5x^3)# ? How do you use the product rule to find the derivative of #y=sqrt(x)*e^x# ? How do you use the product rule to find the derivative of #y=x*ln(x)# ? See all questions in Product Rule Impact of this question 1160 views around the world You can reuse this answer Creative Commons License