Question

What is the derivative of `y = 10^(1-x^2)`?

Answer 1

`y' = -2\ln (10) \ x \ 10^{1-x^2}` x

Explanation:

take natural logs

`\ln y = \ln (10^(1- x^2)) = (1- x^2) \ln (10)`

`\\frac{1}{y} y' = - 2x \ln( 10)`

`y' = - 2x \ln 10 \times y = -2\ln (10) \ x \ 10^{1-x^2}`