What is the derivative of #y= log (6x-2)#? Calculus Differentiating Logarithmic Functions Differentiating Logarithmic Functions without Base e 1 Answer Bill K. Aug 14, 2015 #dy/dx=6/(ln(10)(6x-2))# Explanation: Assuming #log(6x-2)=log_{10}(6x-2)#, the Chain Rule and the fact that #d/dx(log_{10}(x))=1/(ln(10)x)# imply that #dy/dx=6/(ln(10)(6x-2))# when #y=log(6x-2)#. Answer link Related questions What is the derivative of #f(x)=log_b(g(x))# ? What is the derivative of #f(x)=log(x^2+x)# ? What is the derivative of #f(x)=log_4(e^x+3)# ? What is the derivative of #f(x)=x*log_5(x)# ? What is the derivative of #f(x)=e^(4x)*log(1-x)# ? What is the derivative of #f(x)=log(x)/x# ? What is the derivative of #f(x)=log_2(cos(x))# ? What is the derivative of #f(x)=log_11(tan(x))# ? What is the derivative of #f(x)=sqrt(1+log_3(x)# ? What is the derivative of #f(x)=(log_6(x))^2# ? See all questions in Differentiating Logarithmic Functions without Base e Impact of this question 2932 views around the world You can reuse this answer Creative Commons License