Question

What is the derivative of `y = log (x^2 + 1)`?

Answer 1

Assuming `log_10` I found: `y'=(2x)/((x^2-1)*ln(10)`

Explanation:

You can use the Chain Rule to derive the `log` first as it is and then multiply by the derivative of the argument:
`y'=1/((x^2+1)*ln(10))xx(2x)=(2x)/((x^2-1)*ln(10)`