Question

What is the distance between #(–2, 0, 1) `and`(0, 4, –2) #?

Answer 1

`d=2sqrt14`

Explanation:

The distance between two points `(x_1,y_1,z_1)` and `(x_2,y_2,z_2)` in 3-space is given by the following formula

`d=sqrt ((x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2)`

In the case of `(-2,0,4)` and `(0,4,-2)`, the distance between them is

`d=sqrt((0--2)^2+(4-0)^2+(-2-4)^2)=sqrt(4+16+36)=sqrt56=2sqrt14`