What is the distance between #(3, 0) # and #(6,6)#?

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Answer 1 · 2018-03-05T21:08:26

#d=sqrt(45)=9*sqrt(5)~~6.71#

#p_1=(3|0)#
#p_2=(6|6)#
#d^2=(x_1-x_2)^2+(y_1-y_2)^2#
#d=sqrt((3-6)^2+(0-6)^2)#
#d=sqrt(9+36)#
#d=sqrt(45)=9*sqrt(5)~~6.71#

Answer 2 · 2018-03-05T21:10:01

I will show the method, you do the math!!

The distance between two points #(x_1,y_1)# and #(x_2,y_2)#

is given by:

#sqrt((x_2 -x_1)^2 + (y_2 -y_1)^2)#