Question

What is the domain and range for `y = x^2 + 86`?

Answer 1

Domain `(-oo,+oo)` Range [86, `+oo`)

The domain of this function are all real values of x that is `(-oo,+oo)`

If it is solved for x, x= `+-sqrt(y-86)`

Y can not have any value less than 86, because that would make x not a real number. Hence y would have all real values `>=86`.

The Range is thus `[86, +oo)`