Question

What is the domain and range of `x =(y+2)^2`?

Answer 1

Domain: `[0, oo)`, Range: `[-2, oo)`

Explanation:

To graph, you need to solve for `y`:

Square root both sides: `sqrt(x) = y+2`
Isolate the variable `y`: `y =sqrt(x) -2`

Analytically finding the domain:
`sqrt(x) >=0` which means `x>=0`

If `x>=0` then `y >= -2`

From the graph: graph{sqrt(x) - 2 [-10, 10, -5, 5]}