What is the domain and range of y=1/2x^2+4y=12x2+4?

1 Answer
Oct 21, 2014

Consider the function y= f(x)y=f(x)

The domain of this function is all the values of x for which the function holds. The range is all those values of y for which the function is valid.

Now, coming to your question.
y = x^2 / 2 + 4y=x22+4
This function is valid for any real value of x. Thus the domain of this function is the set of all real numbers, i.e. , RR.

Now, separate out x.
y= x^2 /2 +4y=x22+4

=> y-4 = x^2 /2y4=x22

=> 2(y-4) = x^22(y4)=x2

=> {2(y-4)}^(1/2) = x{2(y4)}12=x

Thus, the function is valid for all real numbers greater than or equal to 4. Therefore the range of this function is [4, oo).