What is the domain and range of #y(x)=ln(x+2)#?

Question

4399 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-21T12:00:38

The domain is #x in (-2, +oo)#.
The range is # y in RR#

What's in the log function is #>0#

Therefore,

#x+2 >0#

#x > -2#

The domain is #x in (-2, +oo)#

Let #y=ln(x+2)#

#x+2=e^y#

#x=e^y-2#

#AA y in RR, e^y>0#

The range is # y in RR#

graph{ln(x+2) [-8.54, 23.5, -9.32, 6.7]}