What is the domain of $f (x) = \sqrt{x^{2} (x - 3) (x - 4)}$ $f(x) = sqrt(x^2(x-3)(x-4))$ ?

Question

What is the domain of $f (x) = \sqrt{x^{2} (x - 3) (x - 4)}$ $f(x) = sqrt(x^2(x-3)(x-4))$ ?

1 Answer

Impact of this question

1955 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-09-09T09:20:35

This function is defined for positive values of the quantity under the root.

Explanation:

So in essence you have to find the values for which $(x - 3) \cdot (x - 4)$ $(x-3) * (x-4)$ is positive. If you graph it that happends for values $x \geq 4, x \leq 3$ $x>=4,x<=3$

So the domain is $(- \infty, 3] \cup [4, + \infty)$ $(-oo ,3] uu [4,+oo)$ .

Science

Math

Humanities

... and beyond

What is the domain of $f (x) = \sqrt{x^{2} (x - 3) (x - 4)}$ $f(x) = sqrt(x^2(x-3)(x-4))$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

What is the domain of f(x)=√x2(x−3)(x−4)f(x) = sqrt(x^2(x-3)(x-4))?

1 Answer

Explanation:

Related questions

Impact of this question

What is the domain of $f (x) = \sqrt{x^{2} (x - 3) (x - 4)}$ $f(x) = sqrt(x^2(x-3)(x-4))$ ?