What is the empirical formula of a compound composed of 43.64% P and 56.36% O by mass?

1 Answer
Mar 22, 2016

P2O5 is the empirical formula, the simplest WHOLE number ratio that defines constituent atoms in a species.

Explanation:

We assume that there are 100 g unknown, and work out the proportion of phosphorus and oxygen atoms.

In 100g of stuff there are 43.64g phosphorus and 56.36g oxygen.

We divide thru by the ATOMIC masses of each constituent:

O: 56.36g16.00gmol1 = 3.52mol oxygen

P: 43.64g31.00gmol1 = 1.41mol phosphorus.

We divide thru by the SMALLEST molar quantity, we want to get whole numbers:

3.52mol1.41mol = 2.5 oxygen

1.41mol1.41mol = 1 phosphorus

A formula of PO2.5 is no good to us at all. Why, because as we have specified, the empirical formula is the simplest WHOLE NUMBER RATIO defining constituent atoms in a species. So, we simply double the ration to give P2O5 as required. If the molecular mass of this material is 283.89 gmol1, what is the molecular formula of this material???