What is the equation in slope-intercept form of the line: $2 y - 4 x = - 2$ $2y -4x=- 2$ ?

Question

7623 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-01-06T12:42:09

$y = 2 x - 1$ $y = 2x - 1$

The slope-intercept form of a linear equation is:

$y = m x + b$ $y = color(red)(m)x + color(blue)(b)$

Where $m$ $color(red)(m)$ is the slope and $b$ $color(blue)(b$ is the y-intercept value.

To transform this equation to this form we can solve for $y$ $y$ ;

$2 y - 4 x = - 2$ $2y - 4x = -2$

$2 y - 4 x + 4 x = - 2 + 4 x$ $2y - 4x + color(red)(4x) = -2 + color(red)(4x)$

$2 y - 0 = 4 x - 2$ $2y - 0 = color(red)(4x) - 2$

$2 y = 4 x - 2$ $2y = color(red)(4x) - 2$

$\frac{2 y}{2} = \frac{4 x - 2}{2}$ $(2y)/color(red)(2) = (4x - 2)/color(red)(2)$

$(color(red)(cancel(color(black)(2)))y)/cancel(color(red)(2)) = (4x)/color(red)(2) - 2/color(red)(2)$

$y = 2x - 1$

What is the equation in slope-intercept form of the line: 2y -4x=- 22y−4x=−22y -4x=- 2?