What is the equation of a line that passes through the point (10, 5) and is perpendicular to the line whose equation is y=54x−2 ?

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Answer 1 · 2018-06-29T13:57:52

Equation of line with slope #-1/54# and passing through #(10,5) # is

#color(green)(x + 54y = 280#

#y = 54x - 2#

Slope #m = 54#

Slope of perpendicular line #m_1 = 1/-m = -1/54#

Equation of line with slope #-1/54# and passing through #(10,5) # is

#y - 5 = -(1/54) *(x - 10)#

#54y - 270 = -x + 10#

#x + 54y = 280#