What is the equation of the circle with a center at $(2, 1)$ $(2 ,1 )$ and a radius of $2$ $2$ ?

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Answer 1 · 2016-01-26T22:52:36

${(x - 2)}^{2} + {(y - 1)}^{2} = 4$ $(x-2)^2+(y-1)^2=4$

The standard form of a circle with a center at $(h, k)$ $(h,k)$ and a radius $r$ $r$ is

${(x - h)}^{2} + {(y - k)}^{2} = r^{2}$ $(x-h)^2+(y-k)^2=r^2$

Since the center is $(2, 1)$ $(2,1)$ and the radius is $2$ $2$ , we know that

${(h=2),(k=1),(r=2):}$

Thus, the equation of the circle is

$(x-2)^2+(y-1)^2=2^2$

This simplifies to be

$(x-2)^2+(y-1)^2=4$

What is the equation of the circle with a center at (2 ,1 )(2,1)(2 ,1 ) and a radius of 2 22 ?