What is the equation of the line perpendicular to #y=2/15x # that passes through # (-4,4) #?

Question

1621 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-21T11:00:23

Equation of the line is #y = -15/2 x -26#

Slope of the line, # y=2 /15 x ; [y=m x+c]#

is #m_1= 2/15# [Compared with slope-intercept form of equation]

The product of slopes of the pependicular lines is #m_1*m_2=-1#

#:.m_2= -15/2#. The equation of line passing through

#(x_1,y_1)# having slope of #m_2# is #y-y_1=m_2(x-x_1)#.

The equation of line passing through #(-4,4)# having slope of

#-15/2# is #y-4=-15/2(x+4) or y = -15/2 x +4-30#. or

#y = -15/2 x -26#.

Equation of the line is #y = -15/2 x -26# [Ans]