What is the equation of the line perpendicular to #y=-25/3x # that passes through # (-1,-6) #?

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Answer 1 · 2018-05-08T11:53:53

Equation of the line is #3 x - 25 y =147 #

The slope of the line # y = - 25/3 x [y= m x+c ]#

is #m_1= -25/3# . The product of slopes of the perpendicular lines

is #m_1*m_2=-1 :. m_2 = (-1)/(-25/3)= 3/25#

The slope of the line passing through #(-1,-6) # is # 3/25#

The equation of line passing through #(x_1,y_1)# having slope of

#m# is #y-y_1=m(x-x_1)#.

The equation of line passing through #(-1, -6)# having slope of

#3/25# is #y+6=3/25(x+1) or 25 y +150 = 3 x+3#. or

#3 x - 25 y =147 #

The equation of line is #3 x - 25 y =147 # [Ans]