Question

What is the equation of the line perpendicular to `y=-3/16x` that passes through `(-2,4)`?

Answer 1

If lines are perpendicular then the one slope is the negative reciprocal of the other. this means that `m_1 xx m_2 = -1`

In this case `m_1 = -3/16`
The perpendicular slope to this is `16/3`

Now we have the slope and we also have a point (-2,4).

Use the formula `y - y_1 = m(x - x_1)`

`y -4 = 16/3(x - (-2)) " " rArr y - 4 = 16/3(x + 2)`

`y = 16/3x + 32/3 +4`

`y = 16/3x + 14 2/3`