What is the equation of the line tangent to # f(x)=(3x-1)(2x+4)# at # x=0 #?

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Answer 1 · 2015-12-24T08:04:45

Equation of line:

#y = 10x - 4#

#f(x) = 6x^2 + 10x - 4#

#f(0) = -4# (This is the #y#-intercept of the tangent line)

#f'(x) = 12x + 10#

#f'(0) = 10# (This is the gradient of the tangent line)

Equation of line:

#y = 10x - 4#