What is the equation of the line tangent to #f(x)=e^(3x-4)sine^x# at #x=lnpi#? Calculus Derivatives Tangent Line to a Curve 1 Answer Sonnhard Jun 18, 2018 #y=-pi^4/e^4# Explanation: #f'(x)# is given by #f'(x)=e^(4x-4)*cos(e^x)+3e^(3x-4)*sin(e^x)# and we get #f(ln(pi))=0# since #sin(e^log(pi))=sin(pi)=0# and #f'(ln(pi))=-pi^4/e^4# Answer link Related questions How do you find the equation of a tangent line to a curve? How do you find the slope of the tangent line to a curve at a point? How do you find the tangent line to the curve #y=x^3-9x# at the point where #x=1#? How do you know if a line is tangent to a curve? How do you show a line is a tangent to a curve? How do you find the Tangent line to a curve by implicit differentiation? What is the slope of a line tangent to the curve #3y^2-2x^2=1#? How does tangent slope relate to the slope of a line? What is the slope of a horizontal tangent line? How do you find the slope of a tangent line using secant lines? See all questions in Tangent Line to a Curve Impact of this question 1380 views around the world You can reuse this answer Creative Commons License