What is the equation of the line that passes through (-3,-1) and has a slope of 2/5 ?

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Answer 1 · 2018-04-16T02:54:23

$\Rightarrow y = \frac{2}{5} x + \frac{1}{5}$ $=>y = 2/5x + 1/5$

Point-slope equation of a line:

$\Rightarrow y_{1} - y = m (x_{1} - x)$ $=> y_1 - y = m(x_1 - x)$

Now we solve for $y$ $y$ :

$\Rightarrow - 1 - y = (\frac{2}{5}) (- 3 - x)$ $=> -1 - y = (2/5)(-3-x)$

$\Rightarrow - 1 - y = - \frac{6}{5} - \frac{2}{5} x$ $=>-1-y = -6/5 -2/5x$

$\Rightarrow - y = - \frac{1}{5} - \frac{2}{5} x$ $=> -y = -1/5 - 2/5x$

$\Rightarrow y = \frac{1}{5} + \frac{2}{5} x$ $=> y = 1/5 + 2/5 x$

$\Rightarrow y = \frac{2}{5} x + \frac{1}{5}$ $=> color(blue)(y = 2/5x + 1/5 )$