What is the equation of the oblique asymptote $f(x) = (x^2+1)/(x-1)$ ?

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Answer 1 · 2015-10-29T00:03:41

$y=x+1$

I think you mean the slant asymptote. Simply divide the numerator by the denominator using long division, then ignore the remainder.

Answer: $y=x+1$

hope that helps

What is the equation of the oblique asymptote f(x) = (x^2+1)/(x-1) f(x) = (x^2+1)/(x-1)?