Question

What is the equation of the oblique asymptote `f(x) = (x^2+x-2)/(x+1)`?

Answer 1

`y = x`

Explanation:

`f(x)=(x^2+x-2)/(x+1) = (x(x+1)-2)/(x+1) = x-2/(x+1)`

As `x->+-oo` we have `-2/(x+1) -> 0`.

So `f(x)` has an oblique asymptote with equation `y = x`