What is the exact solution for log(1-x)=3?

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Answer 1 · 2018-06-18T10:18:29

#x=1-e^3#

We write
#log_e (1-x)=3#
so we get

#1-x=e^3#
#x=1-e^3#
We use

#log_a b=n# if #a^n=b#

Answer 2 · 2018-06-18T13:39:14

#x=-999#

I assume that this is written under the usual base #10#.

Given: #log(1-x)=3#.

#:.log_10(1-x)=3#

#1-x=10^3# due to logarithm definitions

#1-x=1000#

#-x=1000-1#

#=999#

#:.x=-999#