What is the exact solution for log(1-x)=3?

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Answer 1 · 2018-06-18T10:18:29

$x=1-e^3$

We write
$log_e (1-x)=3$
so we get

$1-x=e^3$
$x=1-e^3$
We use

$log_a b=n$ if $a^n=b$

Answer 2 · 2018-06-18T13:39:14

$x=-999$

I assume that this is written under the usual base $10$ .

Given: $log(1-x)=3$ .

$:.log_10(1-x)=3$

$1-x=10^3$ due to logarithm definitions

$1-x=1000$

$-x=1000-1$

$=999$

$:.x=-999$